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Simplify the "ids" structure returned by findReferencedElements

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It was a dict with a two element list a la:

  {
    "id1": [len(nodeListX), nodeListX]],
    "id2": [len(nodeListY), nodeListY]],
    ...
  }

This can trivially be simplified to:

  {
    "id1": nodeListX,
    "id2": nodeListY,
    ...
  }

The two call-sites that actually needs the length (e.g. to sort by how
often the id is used) can trivially compute that via a call to "len".

All other call sites either just need to tell if an ID is used at all
or work the nodes referencing the id (e.g. to remap the id).  The
former are unaffected by this change and the latter can now avoid a
layer of indirection.

This refactoring has negiable changes to the runtime and probably also
to memory (not tested, but it is a minor constant improvement per
referenced id).

Signed-off-by: Niels Thykier <niels@thykier.net>
This commit is contained in:
Niels Thykier 2018-02-17 10:02:16 +00:00 • committed by Eduard Braun
parent b916a189e9
commit c54a7239e7
1 changed files with 11 additions and 16 deletions
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27
scour/scour.py
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@ -586,10 +586,9 @@ def findReferencedElements(node, ids=None):
# we remove the hash mark from the beginning of the id
id = href[1:]
if id in ids:
ids[id][0] += 1
ids[id][1].append(node)
ids[id].append(node)
else:
ids[id] = [1, [node]]
ids[id] = [node]
# now get all style properties and the fill, stroke, filter attributes
styles = node.getAttribute('style').split(';')
@ -620,10 +619,9 @@ def findReferencingProperty(node, prop, val, ids):
if len(val) >= 7 and val[0:5] == 'url(#':
id = val[5:val.find(')')]
if id in ids:
ids[id][0] += 1
ids[id][1].append(node)
ids[id].append(node)
else:
ids[id] = [1, [node]]
ids[id] = [node]
# if the url has a quote in it, we need to compensate
elif len(val) >= 8:
id = None
@ -635,10 +633,9 @@ def findReferencingProperty(node, prop, val, ids):
id = val[6:val.find("')")]
if id is not None:
if id in ids:
ids[id][0] += 1
ids[id][1].append(node)
ids[id].append(node)
else:
ids[id] = [1, [node]]
ids[id] = [node]
def removeUnusedDefs(doc, defElem, elemsToRemove=None, referencedIDs=None):
@ -721,7 +718,7 @@ def shortenIDs(doc, prefix, unprotectedElements=None):
# descending, so the highest reference count is first.
# First check that there's actually a defining element for the current ID name.
# (Cyn: I've seen documents with #id references but no element with that ID!)
idList = [(referencedIDs[rid][0], rid) for rid in referencedIDs
idList = [(len(referencedIDs[rid]), rid) for rid in referencedIDs
if rid in unprotectedElements]
idList.sort(reverse=True)
idList = [rid for count, rid in idList]
@ -790,7 +787,7 @@ def renameID(doc, idFrom, idTo, identifiedElements, referencedIDs):
# exactly like findReferencedElements would.
# Cyn: Duplicated processing!
for node in referringNodes[1]:
for node in referringNodes:
# if this node is a style element, parse its text into CSS
if node.nodeName == 'style' and node.namespaceURI == NS['SVG']:
# node.firstChild will be either a CDATA or a Text node now
@ -1307,12 +1304,10 @@ def collapseSinglyReferencedGradients(doc):
identifiedElements = findElementsWithId(doc.documentElement)
# make sure to reset the ref'ed ids for when we are running this in testscour
for rid, nodeCount in six.iteritems(findReferencedElements(doc.documentElement)):
count = nodeCount[0]
nodes = nodeCount[1]
for rid, nodes in six.iteritems(findReferencedElements(doc.documentElement)):
# Make sure that there's actually a defining element for the current ID name.
# (Cyn: I've seen documents with #id references but no element with that ID!)
if count == 1 and rid in identifiedElements:
if len(nodes) == 1 and rid in identifiedElements:
elem = identifiedElements[rid]
if (
elem is not None and
@ -1437,7 +1432,7 @@ def removeDuplicateGradients(doc):
# for each element that referenced the gradient we are going to replace dup_id with master_id
dup_id = dupGrad.getAttribute('id')
funcIRI = re.compile('url\\([\'"]?#' + dup_id + '[\'"]?\\)') # matches url(#a), url('#a') and url("#a")
for elem in referencedIDs[dup_id][1]:
for elem in referencedIDs[dup_id]:
# find out which attribute referenced the duplicate gradient
for attr in ['fill', 'stroke']:
v = elem.getAttribute(attr)